x^2=25^12

Solution for x^2=25^12 equation:

x^2=25^12

We move all terms to the left:

x^2-(25^12)=0

We add all the numbers together, and all the variables

x^2-59604644775390625=0

a = 1; b = 0; c = -59604644775390625;
Δ = b2-4ac
Δ = 02-4·1·(-59604644775390625)
Δ = 238418579101562500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{238418579101562500}=488281250$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-488281250}{2*1}=\frac{-488281250}{2}
=-244140625
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+488281250}{2*1}=\frac{488281250}{2}
=244140625
$